riemann39s-quaternary-conjecture
Original: riemann39s-quaternary-conjecture on Saturday Morning Breakfast Cereal
Transcript
Panel 1:
Man with reddish hair (in red shirt): WELL, ACCORDING TO RIEMANN'S QUATERNARY CONJECTURE, IF YOU TAKE A NUMBER THAT IS EQUAL TO FOUR AND ADD IT TO ITSELF ENOUGH TIMES, THE RESULT IS e.
Man: NOT EULER'S CONSTANT. JUST THE LETTER e.
(A woman with brown hair, seen from behind, faces him.)
Caption below panel:
Funtime Activity:
Finding people with the last name Riemann and paying them to say stupid things.
Votey:
Handwritten note: Also, according to Fermat, a^ + b^ = 5
Man with reddish hair (in red shirt): WELL, ACCORDING TO RIEMANN'S QUATERNARY CONJECTURE, IF YOU TAKE A NUMBER THAT IS EQUAL TO FOUR AND ADD IT TO ITSELF ENOUGH TIMES, THE RESULT IS e.
Man: NOT EULER'S CONSTANT. JUST THE LETTER e.
(A woman with brown hair, seen from behind, faces him.)
Caption below panel:
Funtime Activity:
Finding people with the last name Riemann and paying them to say stupid things.
Votey:
Handwritten note: Also, according to Fermat, a^ + b^ = 5
Alt text
A man with reddish-brown hair in a red shirt earnestly tells a brown-haired woman (shown from behind): "Well, according to Riemann's Quaternary Conjecture, if you take a number that is equal to four and add it to itself enough times, the result is e. Not Euler's constant. Just the letter e." The statement is mathematical-sounding nonsense. A caption beneath reads: "Funtime Activity: Finding people with the last name Riemann and paying them to say stupid things." The votey shows a hand-scrawled note continuing the gag: "Also, according to Fermat, a^ + b^ = 5" — mangling Fermat's Last Theorem into a meaningless equation.
Transcribed by Claude Opus 4.8.